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3 years ago

If h(x) = -3x + 1 and h(x) = -20, solve for x.

Mathematics

1 answer:

liraira [26]3 years ago

6 0

Answer:

x=7

Step-by-step explanation:

-20=-3x+1

-21=-3x

x=7

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What value of x makes the equation true? a -3 b -1 c 3 d 1

Ivenika [448]

Answer:

-3

Step-by-step explanation:

cause positive = negative

the answer is = negative

3 0

3 years ago

Best estimate 27x1/7

FinnZ [79.3K]

27/7 or Decimal: 3.857143

8 0

3 years ago

Avicenna, a major insurance company, offers five-year life insurance policies to 65-year-olds. If the holder of one of these pol

ki77a [65]

Answer:

Avicenna can expect to lose money from offering these policies. In the long run, they should expect to lose ___33__ dollars on each policy sold

Step-by-step explanation:

Given :

The amount the company Avicenna must pay to the shareholder if the person die before 70 years = $ 26,500

The value of each policy = $497

It is given that there is a 2% chance that people will die before 70 years and 98% chance that people will live till the age 70.

The expected policy to be sold= policy nominal + chances of death

= 497 + [98% (no pay) + 2% (pay)]

= 497 + [98%(0) + 2%(-26500)]

(The negative sign shows that money goes out of the company)

= 497 - 2% (26500)

= 497 - 530

=33

Therefore the company loses 33 dollar on each policy sold in the long run.

7 0

2 years ago

Use spherical coordinates. evaluate xyz dv e , where e lies between the spheres ρ = 4 and ρ = 6 and above the cone ϕ = π/3.

sergey [27]

Set

$x=\rho\cos\theta\sin\varphi$

$y=\rho\sin\theta\sin\varphi$

$z=\rho\cos\varphi$

so that the volume element is

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

The integral is then

$\displaystyle\iiint_Exyz\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi/3}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=4}^{\rho=6}\rho^5\cos\theta\sin\theta\sin^3\varphi\cos\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\rho$

$=\displaystyle\left(\int_0^{\pi/3}\sin^3\varphi\cos\varphi\,\mathrm d\varphi\right)\underbrace{\left(\int_0^{2\pi}\cos\theta\sin\theta\,\mathrm d\theta\right)}_0\left(\int_4^6\rho^5\,\mathrm d\rho\right)$

and so evaluates to 0.

3 0

3 years ago

Write each function in standard form. y = 3(x - 2)2^2- 4

galben [10]

Answer:

-4

Step-by-step explanation:

7 0

3 years ago