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Novay_Z [31]
3 years ago
7

Five weeks after the introduction of a new toy, the manufacturer found that the demand for the toy was modeled by f(x) = x^2 +5x

+4/x^2+6x-7 - 1/x , while the company s supply capability was modeled by g(x) = - 0.89x^2 +850x -50/(800x+70.5. Here x is the number of weeks the toy has been on the market, and values of f(x) and g(x) are in millions of toy units. About how many weeks after the toy was introduced did supply equal demand? Round to the nearest whole number of weeks.
Mathematics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

76 weeks

Step-by-step explanation:

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What two numbers subtract to 4 and add to 20
Verdich [7]

Answer:

8 & 12

Step-by-step explanation:

12 - 8 = 4

12 + 8 = 20

8 0
3 years ago
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-20-7x=-2x+2 solve the equation
Alex73 [517]

Answer:

-4.4

Step-by-step explanation:

In order to do this, we need to move the variables to one side, and the numerical values to the other.

-20-7x=-2x+2

We can do this by adding 7x to both sides first

-20=5x+2

Now we can subtract 2 from both sides.

-22=5x

Next, we can divide each side by 5.

x=-22/5

Then we simplify the fraction

x=-4.4

3 0
3 years ago
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What is the value of x in the equation as a fraction 2(5x+4)=17
Norma-Jean [14]

Answer:

x= 9/10

Step-by-step explanation:

2(5x+4)=17

Distribute

10x +8 = 17

Subtract 8 from each side

10x+8-8=17-8

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Divid by 10

10x/10 = 9/10

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8 0
3 years ago
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What is another way to write this problem <br>20+9+.1+.06
insens350 [35]
Other ways to write it are:
29 + .16
20.1 + 9.06
20.06 + 9.1
29.1 + .06
29.06 + .1
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7 0
3 years ago
A recent study stated that if a person chewed gum, the average number of sticks of gum he or she chewed daily was 8. Researcher
konstantin123 [22]

Answer:

The average number of sticks of gum a person chewed daily was greater than 8.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 8

Sample mean, \bar{x} = 9

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = 1

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 8\text{ gums}\\H_A: \mu > 8\text{ gums}

We use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{9 - 8}{\frac{1}{\sqrt{36}} } = 6

Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

Since,  

z_{stat} > z_{critical}

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.

Thus, the average number of sticks of gum a person chewed daily was greater than 8.

3 0
4 years ago
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