Answer:
Given that, Vasudevan invested ₹ 60,000
For Compound Interest (C.I.)
A = P[1 + (r/100)]n
P = ₹ 60,000
n = 6 months and 1 year
R = 12% p.a. compounded half-yearly
where , A = Amount, P = Principal, n = Time period and R = Rate percent
(i) For easy calculation of compound interest, we will put Interest Rate as 6% half-yearly and n = 1.
Compound Interest to be paid for 6 months
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]1
A = 60000[(100/100) + (6/100)]
A = 60000 × (106/100)
A = 60000 × 1.06
A = ₹ 63600
(ii) Compound Interest to be paid for 12 months (1 year) compounded half yearly.
So, assume n = 2, r = 6%
A = P[1 + (r/100)]n
A = 60000[1 + (6/100)]2
A = 60000[(100/100) + (6/100)]2
A = 60000 × (106/100) × (106/100)
A = 60000 × (11236/10000)
A = 60000 × 1.1236
A = ₹ 67416
7 is the missing numerator in the equivalent fraction with a denominator of 2.
<u>Step-by-step explanation</u>:
The mixed fraction is 3 1/2.
- Convert it into a proper fraction to get a equivalent fraction.
- Multiply the denominator 2 with 3 and then add 1 to the answer.
⇒ 3 1/2 = ((3
2) + 1)/2
⇒ 3 1/2 =7/2
∴ The numerator of the equivalent fraction is 7.
Answer:
60 × 50 = 3000
7 × 50 = 350
60 × 4 = 240
7 × 4 = 28
3000 + 350 + 240 + 28 =3618
54 × 67 = 3618
Answer:
124
Step-by-step explanation:
When x=4, substitute 4 into the function to give f(4).
The answer for 25 is y=3x+1
The answer for 24 is y=3x+5
