Answer:


Step-by-step explanation:
For p'(4):


For q'(8):


Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
hope the above solution will help you
Answer:
the question is incorrect.
Answer:
B. No, the remainder is -50.
General Formulas and Concepts:
<u>Algebra I</u>
- Roots are when the polynomial are equal to 0
<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define</u>
Function f(x) = x³ - 10x² + 27x - 12
Divisor/Root (x + 1)
<u>Step 2: Synthetic Division</u>
<em>See Attachment.</em>
To determine whether a given root is an actual root, the remainder must equal 0. Since we have a remainder of -50, the given root is not a factor of the polynomial.
<em>Please excuse the bad handwriting. Hope this helped!</em>