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Annette [7]
2 years ago
11

Thanks who ever helped ​

Mathematics
1 answer:
NeTakaya2 years ago
3 0

Answer:

60 × 50 = 3000

7 × 50 = 350

60 × 4 = 240

7 × 4 = 28

3000 + 350 + 240 + 28 =3618

54 × 67 = 3618

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Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
Read 2 more answers
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
2 years ago
Really Need Help ! ASAP
SCORPION-xisa [38]

Answer:

hope the above solution will help you

5 0
3 years ago
N to the second power - 5 in - 1 in equals 6​
Wittaler [7]

Answer:

the question is incorrect.

4 0
3 years ago
HELP WILL GIVE BRAINLIEST IF CORRECT
mart [117]

Answer:

B. No, the remainder is -50.

General Formulas and Concepts:

<u>Algebra I</u>

  • Roots are when the polynomial are equal to 0

<u>Algebra II</u>

  • Synthetic Division

Step-by-step explanation:

<u>Step 1: Define</u>

Function f(x) = x³ - 10x² + 27x - 12

Divisor/Root (x + 1)

<u>Step 2: Synthetic Division</u>

<em>See Attachment.</em>

To determine whether a given root is an actual root, the remainder must equal 0. Since we have a remainder of -50, the given root is not a factor of the polynomial.

<em>Please excuse the bad handwriting. Hope this helped!</em>

6 0
3 years ago
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