Question

Claim: The mean pulse rate (in beats per minute, or bpm) of adult males is equal to 69 bpm. For the random sample of 153 adult males in Data Set 1 "Body Data" in Appendix B, the mean pulse rate is 69.6 bpm and the standard deviation is 11.3 bpm. Only identify the null and alternative hypothesis.

Answer 1

Answer:

$H_0:\mu=69$

$H_a:\mu\neq69$

Step-by-step explanation:

We know that ,

Null hypothesis$(H_0)$ is a statement that contains the population parameter to represent claim or against claim statement along with = , ≤ and ≥ signs.

Where as Alternative hypothesis$(H_a)$ is also a statement that contains the population parameter but against the null hypothesis . It contains ≠ , < and > signs.

In the given situation, the population parameter is population mean $(\mu)$ .

Claim: The mean pulse rate (in beats per minute, or bpm) of adult males is equal to 69 bpm.

i.e. $H_0:\mu=69$

and $H_a:\mu\neq69$    [Against $H_0$]