Answer: 0.87
Step-by-step explanation:
Its the closet i can get
Answer:
a) we have the numbers 0, 2, 3, 5, 5. The mean and the median are both 3
b) we have the numbers 0, 0, 3, 5, 7. The mean and the median are both 3
In both cases the mean and the median are 3, but the mode differs. The mean and the median do not uniquely determine the mode.
Step-by-step explanation:
Answer:
Part A: No it is not a function
Part B: The equation
Part C: x = 3
Step-by-step explanation:
Part A - The table:
Input (x) Output (y)
6 14
12 15
15 15
25 16
This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.
Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.
y = 7(6) -15
y = 42 - 15
y = 27
The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.
Part C: To find when y = 6, set it equal to 6 and solve for x.
6 = 7x - 15
21 = 7x
3 = x
Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
