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Virty [35]
3 years ago
12

What is an online reputation?

Computers and Technology
2 answers:
taurus [48]3 years ago
8 0

Answer:

Reputation management refers to the influencing and controlling or concealing of an individual's or group's reputation

Explanation:

Hitman42 [59]3 years ago
3 0

Answer:

An online reputation is the reputation of a company, person, product,service, or any other element on the internet or digital platforms.

You might be interested in
Implement function hex2dec that takes a hex number hex_num as a string argument and prints out the corresponding decimal number.
DerKrebs [107]

Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void hex2dec(string hex_num){

int n = 0;

//Loop through all characters in string

for(int i=0;i<hex_num.size();i++){

//take ith character

char c = hex_num[i];

//Check if c is digit

if(c>='0' && c<='9'){

n = 16*n + (c-48);

}

//Convert c to decimal

else{

n = 16*n + (c-55);

}

}

cout<<hex_num<<" : "<<n<<endl;

}

int main()

{

hex2dec("EF10");

hex2dec("AA");

return 0;

}

The Output can be seen below :

4 0
3 years ago
What is the function of ctrl+Q​
vlabodo [156]

Answer:

Ctrl+Q is used to remove a paragraph's formatting

Explanation:

Hope that's the answer you're looking for!

5 0
2 years ago
Given a vector of students, the function FinalAvg is supposed to return the average final exam score across all the students in
alexandr1967 [171]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#define CATCH_CONFIG_MAIN //This tells Catch to provide a main()

#include"catch.hpp" //Header for Catch Framework

double FinalAvg( vector <int> students) // Function to calculate average.

{

double sum =0;

int i;

for( i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/ v.size());

}

vector<int> func(int argvq[ ]) // This function is made because we can not provide vector in command line argument that's why we used array which is then conerted into vector.

{

vector<int> v;

int j;

int l= sizeof(argvq)/sizeof(argvq[0]);

for(j=0;j<l;j++)

v.push_back(argq[j]);

return v;

}

TEST_CASE(" Final Average marks are computed","[func]") // TEST_ CASE macro to take one or more arguments

{

REQUIRE( func(9,5,-7) == 7); // We write our individual test assertions using the REQUIRE macro.

REQUIRE(func(2,4,6,-2) ==4);

}

Explanation Using different IDE:

#include<bits/stdc++.h>

using namespace std;

double FinalAvg(vector<int> students)

{

double sum=0;

for(int i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/v.size());

}

int main()

{

vector<int> v;

int i;

while(cin>>i&&i>0) v.push_back(i);

cout<<Final Avg(v);

return 0;

}

8 0
3 years ago
You and a few friends are having a meal at a pizza restaurant, and the server has just given you the bill. Write a function that
cestrela7 [59]

Answer:

How to calculate the total cost of the meal

For bill inclusive of tax, cost1=cost*(1+tax percentage)

For bill inclusive of tax and tip, cost2=cost1*(1+tip percentage)

Meal cost =(pizza cost*(1+tax percentage))*(1+tip percentage)

Now how to calculate the cost per person

cost per person=meal cost/ number of people.

C language code to solve the above problem is given below with appropriate comments for explanation

Explanation:

#include<stdio.h>

float split_bill(int cost,float tax)

{

//Declaring number of people as int

int number;

//Prompting for number of people

printf("Enter number of people ");

scanf("%d",&number);

//Declaring tip percentage as float

float tip_percent;

//Prompting for tip percentage

printf("Enter tip percentage between 0 and 1 ");

scanf("%f",&tip_percent);

//Calculating total meal cost

float meal=(((float)cost)*(1+tax))*(1+tip_percent);

//Printing total cost of meal

printf("Total cost of meal: %0.2f ",meal);

//Calculating cost per person

float cost_per_person=meal/number;

//Returning cost per person to main function

return cost_per_person;

}

int main()

{

//Declaring pizza cost as int and tax percentage as float

int pizza_cost;

float tax_percent;

//Prompting user for pizza cost

printf("Enter billing amount of pizza ");

scanf("%d",&pizza_cost);

//Prompting user for tax percentage

printf("Enter tax percentage between 0 and 1 ");

scanf("%f",&tax_percent);

//Printing the cost per person by calling the function split_bill

printf("Total cost per person is: %0.2f ",split_bill(pizza_cost,tax_percent));

return 0;

}

8 0
3 years ago
Using Module operator, write a java program to print odd number between 0 and 1000​
jolli1 [7]

Answer:

class OddNumber

{

  public static void main(String args[])  

       {

         int n = 1000;  //Store 1000 in Variable n typed integer

         System.out.print("Odd Numbers from 1 to 1000 are:");  // Print headline of output window

         for (int i = 1; i <= n; i++)  //For loop to go through each number till end

          {

            if (i % 2 != 0)  //check if number is even or odd.Not divisible by 2 without reminder means it is odd number

             {

               System.out.print(i + " "); //print odd numbers

             }

          }

       }

}              

5 0
3 years ago
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