Answer:
The answer is A4B₁₆ = 2635₁₀ = 101001001011₂
Explanation:
To convert from hexadecimal base system to binary base system, first you can do an intermediate conversion from hexadecimal to decimal using this formula:
where position of the x₁ is the rightmost digit of the number and the equivalents hexadecimal numbers to decimal:
- A = 10.
- B = 11.
- C = 12.
- D = 13.
- E = 14.
- F = 15.
A4B₁₆ = A*16²+4*16¹+B*16⁰ = 2560 + 64 + 11 = 2635₁₀
Now, you have the number transformed from hexadecimal to decimal. To convert the decimal number 2635 to binary: Divide the number repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to 0:
2635 ÷ 2 = 1317 + 1;
1317 ÷ 2 = 658 + 1;
658 ÷ 2 = 329 + 0;
329 ÷ 2 = 164 + 1;
164 ÷ 2 = 82 + 0;
82 ÷ 2 = 41 + 0;
41 ÷ 2 = 20 + 1;
20 ÷ 2 = 10 + 0;
10 ÷ 2 = 5 + 0;
5 ÷ 2 = 2 + 1;
2 ÷ 2 = 1 + 0;
1 ÷ 2 = 0 + 1;
Now, construct the integer part base 2 representation, by taking the remainders starting from the bottom of the list:
2635₁₀ = 101001001011₂
Answer:
import java.util.Scanner;
public class WeeklySalary {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter Hourly wage");
double hourlyWage = in.nextDouble();
System.out.println("Enter total hours worked in the week");
int hoursWorked = in.nextInt();
int overtime = hoursWorked - 40;
double weeklyWage = 40*hourlyWage;
System.out.println("Total Over Time Hours is: "+overtime);
double overTimeWage = overtime*(hourlyWage*1.5);
System.out.println("Wage for full time: "+ weeklyWage);
System.out.println("Wage for over time: "+ overTimeWage);
}
}
Explanation:
- Using Java programming language
- Import the Scanner class to receive user input
- prompt user for hourly wage rate, receive and save in a variable
- Prompt user for total hours worked for the week receive and save in a variable
- calculate overtime hours by subtracting 4 from total hours worked in the week
- Calculate weekly wage by multiplying hourly rate by 40
- Calculate overtime by multiplying overtime hours by (hourlyWage*1.5).
- See attached sample run of the code
B. Which promotes a chemical reaction
Answer:
This is a Answer Not Question... But Answering it to explain what it is.
Explanation: