Answer:
It will take 6 hours for the new pump to drain the pool.
Step-by-step explanation:
As the complete question is not given, the complete question is found online and is attached herewith
Let the rate of new pump is given as x=W/t_1
Let the rate of the old pump is given as y=W/t_2
it is given that the time t_2=2t_1
So by substituting the values of t_2 in the rate equation of y
y=W/2t_1
y=(W/t_1*2)=x/2
Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes
x+y=W/4
x+x/2=W/4
3x/2=W/4
As x=W/t_1
3W/2t_1=W/4
Now as W is same on both sides so
3/2t_1=1/4
12=2t_1
t_1=6 hours
So it will take 6 hours for the new pump to drain the pool.
Answer:
-200 | -500 | -500-(-200) | -300
-200 | -0 | 0 -(-200) | 200
Step-by-step explanation:
Answer:
you got this kiddo
Step-by-step explanation:
Answer:
6.75
Step-by-step explanation:
You would use the point-slope equation of y-y₁=mx(x-x₁)
So the rate of change is the slope and equals m, so m=-4
and has a solution at (-5,2) which would be the (x₁, y₁) and then it is just plugging in the numbers
y - (2) = (-4)(x - (-5))
y - 2 = -4 (x+5)
y - 2 = -4x - 20
y = -4x - 18