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Brilliant_brown [7]
3 years ago
5

Which model represents a fraction greater than Three-fifths? A circle divided into 5 equal parts. One part is shaded. A circle d

ivided into 10 equal parts. 5 parts are shaded. A circle divided into 6 equal parts. 2 parts are shaded. A circle divided into 10 equal parts. 8 parts are shaded.
Mathematics
2 answers:
andre [41]3 years ago
6 0

Answer:

A circle divided into 10 equal parts with 8 parts shaded= Answer D

Step-by-step explanation:

PLEASE MARK BRAINLiEST

write them down as fractions so its easier to compare.

A circle divided into 5 parts with 1 part shaded = 1/5

A circle divided into 10 parts with 5 parts shaded = 5/10

A circle divided into 6 parts with 2 parts shaded = 1/3

A circle divided into 10 parts with 8 parts shaded = 8/10

we can see that they don't have a common denominator so lets fix that

1/5 = 6/30

5/10 = 15/30

1/3 = 10/30

8/10 = 24/30

3/5 = 18/30

find which one is greater than 3/5

Only the 24/30 one is greater, and looking back that is the circle divided into 10 parts with 8 of them shaded.

alexandr402 [8]3 years ago
4 0

Answer: A circle divided into 10 equal parts with 8 parts shaded

Step-by-step explanation:

Alright, there are a lot of words here so lets write them down as fractions so its easier to compare.

A circle divided into 5 parts with 1 part shaded = 1/5

A circle divided into 10 parts with 5 parts shaded = 5/10

A circle divided into 6 parts with 2 parts shaded = 1/3

A circle divided into 10 parts with 8 parts shaded = 8/10

Okay so looking at this we can see that they don't have a common denominator so lets fix that

1/5 = 6/30

5/10 = 15/30

1/3 = 10/30

8/10 = 24/30

3/5 = 18/30

Now lets find which one is greater than 3/5

Only the 24/30 one is greater, and looking back that is the circle divided into 10 parts with 8 of them shaded.

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Suppose the coefficient matrix of a linear system of four equations in four variables has a pivot in each column. Explain why th
Veseljchak [2.6K]

If the coefficient matrix has a pivot in each column, it means that it is shaped like this:

A=\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]

So, the correspondant system

Ax = b

will look like this:

\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]\cdot \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{c}b_1\\b_2\\b_3\\b_4\end{array}\right]

This turn into the following system of equations:

\begin{cases}a_{1,1}x_1+a_{1,2}x_2+a_{1,3}x_3+a_{1,4}x_4=b_1\\a_{2,2}x_2+a_{2,3}x_3+a_{2,4}x_4=b_2\\a_{3,3}x_3+a_{3,4}x_4=b_3\\a_{4,4}x_4=b_4\end{cases}

The last equation is solvable for x_4: we easily have

x_4=\dfrac{b_4}{a_{4,4}}

Once the value for x_4 is known, we can solve the third equation for x_3:

x_3 = \dfrac{b_3-a_{3,4}x_4}{a_{3,3}}

(recall that x_4 is now known)

The pattern should be clear: you can use the last equation to solve for x_4. Once it is known, the third equation involves the only variable x_3. Once

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inysia [295]

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Step-by-step explanation:

Dylan because i it has 8 sides and if each student rolls it 200 times, then you should divide 200 by 8. Which would make the odds 1/25. And Dylan´s number is closest to 25.

5 0
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horsena [70]

Answer:

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Step-by-step explanation:

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balu736 [363]

Answer:

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Step-by-step explanation:

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