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ella [17]
2 years ago
14

Someone help with these? I have major problems figuring these out.

Mathematics
1 answer:
zzz [600]2 years ago
4 0
 answers are 110,32,113,72 and 540 degrees
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5/10 =   /6  is 5/10 and 3/6 equivalent fraction.  if so, please explain
Sonja [21]
\frac{5}{10}= \frac{1\cdot5}{2\cdot5}  = \frac{1}{2} \ \ \ and\ \ \  \frac{3}{6}= \frac{1\cdot3}{2\cdot3}  = \frac{1}{2} \ \ \ \ \Rightarrow\ \ \  \frac{5}{10}=\frac{3}{6}
8 0
2 years ago
5/14 in in simple form
slavikrds [6]

Answer:

Step-by-step explanation:

1. Find the GCD ( or HCF) of numerator and denominator

<u>GCD of 5 and 14 is 1</u>

2. Divide both the numerator and denominator by the GCD

5 divide 1 and 14 divide 1

3 reduced fraction

      5/14

7 0
3 years ago
Which graph represents the solution to the compound inequality?
zmey [24]

The graph which represents the solution to the compound inequality is; -2 ≤ x < 5.

<h3>Which graph represents the solution to the compound inequality?</h3>

The inequalities given in the task content can be solved as follows;

For –2x + 4 ≤ 8

-2x ≤ 8 -4

x >= -2

For –2x + 4 > –6

–2x > –6 -4

x < 5

Hence, the graph which represents the solution to the compound inequality is; -2 ≤ x < 5.

Read more on compound inequality;

brainly.com/question/7070563

#SPJ1

3 0
1 year ago
Find the cube root of 512​
Andru [333]

Answer:

the answer is 8

Step-by-step explanation:

cube root of 512 is 8

6 0
2 years ago
(cosxtanx-tanx+2cosx-2)/tanx+2=cosx-1<br> can someone show me how to prove this?
uysha [10]

Answer:

See detail below.

Step-by-step explanation:

A word of caution before getting to the actual problem: I believe there is an important set of brackets missing in the original post. The expression on the left hand side should be:

(cosxtanx-tanx+2cosx-2)/(tanx+2)

Without the brackets, it is left unclear whether the denominator is just tanx or tanx+2. I recommend to use brackets wherever any doubt could arise.

Now to the actual problem: \we can make the following transformations on the left hand side:

\frac{\cos x \tan x + 2\cos x -2}{\tan x +2}=\frac{\cos x \frac{\sin x}{\cos x}  + 2\cos x -2}{\frac{\sin x +2\sin x}{\cos x} }=\\=\frac{\cos x \sin x - \sin x + 2\cos^2 x - 2\cos x}{\sin x + 2\cos x}=\\=\frac{\cos x \sin x +2\cos^2 x }{\sin x + 2\cos x}-1=\\=\cos x -1

which is shown to be the same as the right hand side, which was to be shown.

7 0
2 years ago
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