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azamat
3 years ago
6

Solve the literal equation for y. 2x+5y = 3y+8

Mathematics
1 answer:
ozzi3 years ago
4 0

Answer:

y = -x +4

Step-by-step explanation:

2x+5y = 3y+8

Subtract 3y from each side

2x+5y-3y = 3y-3y+8

2x+2y = 8

Subtract 2x from each side

2x+2y -2x = -2x+8

2y = -2x+8

Divide by 2

2y/2 = -2x/2 +8/2

y = -x +4

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Step-by-step explanation:

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f(0) = 30 and f(n + 1) = f(n) + 7 ......... (1)

Therefore, putting n = 0 in equation (1) we get f(1) = f(0) + 7 = 30 + 7 = 37 {Since, f(0) is given to be 30}

Again, putting n = 1 in equation (1) we get f(2) = f(1) + 7 = 37 + 7 = 44

And, putting n = 2 in equation (1) we get f(3) = f(2) + 7 = 44 + 7 = 51

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Therefore, the arithmetic sequence is 30, 37, 44, 51, .......

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(Answer)

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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