Answer:
No
Step-by-step explanation:
To see if (2,2) is a solution, substitute them into the inequality and see if it is true.
2 is our x value, and 2 is also our y value
y < 4x – 6
2< 4(2)– 6
2 < 8 – 6
2 < 2
This statement is false. 2 is not less than 2, so (2,2) is not a solution to this equation.
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
Answer: B and D
Step-by-step explanation:
Answer:
![xy^3 \sqrt[4]{y^3}](https://tex.z-dn.net/?f=xy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D)
Step-by-step explanation:
Recall the exponent property
.
We can use this property to break the problem down:
![\sqrt[4]{x^4y^{15}}=\sqrt[4]{x\cdot x\cdot x\cdot x\cdot y^3\cdot y^3\cdot y^3\cdot y^3\cdot y^3}=\boxed{xy^3 \sqrt[4]{y^3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4y%5E%7B15%7D%7D%3D%5Csqrt%5B4%5D%7Bx%5Ccdot%20x%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%7D%3D%5Cboxed%7Bxy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D%7D)