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sattari [20]
3 years ago
12

Suppose a shipment of 140 electronic components contains 3 defective components. to determine whether the shipment should be​ ac

cepted, a​ quality-control engineer randomly selects 3 of the components and tests them. if 1 or more of the components is​ defective, the shipment is rejected. what is the probability that the shipment is​ rejected?
Mathematics
2 answers:
Westkost [7]3 years ago
7 0
If its out of the defective components its 1 out of 3 if its the entire shipment its 46% chance it is rejected
 
MA_775_DIABLO [31]3 years ago
4 0
The chance that one of the defective components is \frac{3}{140} or 2.14285714% that the qc person will test a defective unit.
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Which shows the expressions in the order they would appear on a number line from least to greatest?
Illusion [34]
<span>c.)11 over 9, square root of 5, square root of 11, square root of 20, 2 to the power of 3

In order to compare, try to bring all of them into one similar form, like decimal.
Then, 11/9 = 1.22
Then, we can compare numbers under root, as 5 would be smaller than 11 which in turn is smaller than the 20, then 2^3 is 8, largest in series.

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6 0
3 years ago
Read 2 more answers
A 3. A card is pulled from a standard deck of cards.
dexar [7]
<h3>Answer:    4/13</h3>

Explanation:

There are 13 hearts, including the queen of hearts. Then there are 3 more queens to get us to 13+3 = 16 cards we're after.

There are 16 cards we want out of 52 total, so the probability is 16/52 = (4*4)/(4*13) = 4/13

3 0
2 years ago
A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha
lesantik [10]

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

8 0
3 years ago
Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe
bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W  = 100 m

The  largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES  = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter  

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W)   - L  = 2W + L

Now, fencing is given as 500 m

⇒  2W + L  = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L =  2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W  = 100 m

The maximized area = Length x Width

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Hence, the  largest area that can be enclosed is 20,000 sq m.

6 0
3 years ago
I need to know the surface area of these
Nookie1986 [14]
I can barely see the number , too help you out
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