Answer:
((160/3)π + 16√3) in²
Step-by-step explanation:
Together with the radii of 8 inches, the 8-inch chord creates an equilateral triangle with a central angle of 60°, or π/3 radians.
In problem 1, you found the area of the smaller segment to be ...
A = (1/2)r²·(θ -sin(θ))
For θ = π/3 and r = 8 in, this is (1/2)(8 in)²(π/3 -(√3)/2) = ((32/3)π -16√3) in².
The remaining segment of the circle is the area of the circle less this amount, so is ...
π·(8 in)² -(32/3π -16√3) in² = (160/3π +16√3) in² . . . . larger segment area
62/7 = 186/21 all you need to do is how 62 and 186 race related and if you multiply 62 by 3 it = 186, so you do the same with seven and it comes to 21. Both come out to about 8.857
Answer:
∠1, ∠5 and ∠8 (a)
Step-by-step explanation:
∠1 because vertical angles are congruent
∠5 because opposite interior angles are congruent
if ∠5 = 70° then ∠8 also equals 70° because of vertical angles
7/2= 3 1/2, 12/5= 2 2/5, 11/7= 1 4/7, 15/4= 3 3/4
