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irakobra [83]
3 years ago
10

The polygon in each pair are similar.find the missing side length.

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0
Answer is 8 hope this helps!
evablogger [386]3 years ago
4 0

the answer should be 8..

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Solve for x: 5/x^2-4+2/x=2/x-2
IRINA_888 [86]

\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)


5x + 2(x + 2)(x - 2) = 2x(x + 2)


5x + 2(x^2 - 4) = 2x^2 + 4x


5x + 2x^2 - 8 = 2x^2 + 4x


5x - 8 = 4x


x - 8 = 0


x = 8


Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.


Answer: x = 8

6 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
I DONT PAY ATTENTION PLEASE HELP ME AND EXPLAIN IF YOU FEEL LIKE IT
Molodets [167]

Answer: -5x

Step-by-step explanation: combine like terms hope this helps!

6 0
3 years ago
The momentum, p, of an object is represented by the formula p = mv, where m is the mass of the object and v is the velocity of t
Over [174]
B. meters per second
5 0
3 years ago
What is the period of the function below?
sweet-ann [11.9K]

Answer:

4

Step-by-step explanation:

looking at highest peaks

10 - 6 = 4

6 - 2 = 4

3 0
3 years ago
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