The new equation is
<em>Y = (x-8)² </em>.
The other way to write it is like this: (you might not recognize it in this form)
Y = x² - 16x + 64
The average rate of change for the function f(x) can be calculated from the following equation

By applying the last formula on the given equations
(1) the first function f
from the table f(3π/2) = -2 and f(2π) = 0
∴ The average rate of f =

(2) the second function g(x)
from the graph g(3π/2) = -2 and g(2π) = 0
∴ The average rate of g =

(3) the third function h(x) = 6 sin x +1
∴ h(3π/2) = 6 sin (3π/2) + 1 = 6 *(-1) + 1 = -5
h(2π) = 6 sin (2π) + 1 = 6 * 0 + 1 = 1
∴ The average rate of h =
By comparing the results, The <span>function which has the greatest rate of change is h(x)
</span>
So, the correct answer is option <span>
C) h(x)</span>
Answer:
38.29 i think
Step-by-step explanation:
15. -(-7y + 12) = 7y - 12
16. 1/a = 16/18
cross multiply
16a = 18
a = 18/16 = 9/8
17. 8x - 12 = 4x + 24
8x - 4x = 24 + 12
4x = 36
x = 36/4
x = 9
18. -6b > 42 4b > -4
b < 42/-6 b > -4/4
b < - 7 b > -1
so b < -7 and b > -1
19. 6 more then the product of 8 and n
6 + 8n
20. 45 = 3b + 69
45 - 69 = 3b
-24 = 3b
-24/3 = b
-8 = b
Answer:
a) 
b) 
Step-by-step explanation:
Given Data:
Interest rate=
per year
No. of years=
Rate of continuous money flow is given by the function
a) to find the present value of money

Put f(t)=2000 and n=10 years and r=0.08

Now integrate







(b) to find the accumulated amount of money at t=10

Where P is the present worth already calculated in part a



