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4 years ago

Find the amount in an account if $1,220 is invested at 9% compounded quarterly, for 17 years.

1 answer:

5 0

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1220\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &17 \end{cases} \\\\\\ A=1220\left(1+\frac{0.09}{4}\right)^{4\cdot 17}\implies A=1220(1.0225)^{68}\implies A\approx 5539.43$

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Suppose there is a simple index of three stocks, stock X, stock Y, and stock Z.

Pie

Answer:

Step-by-step explanation:

so the first one ends at 4.7107

the second- 3.3568

the third- 5.1401

and multiplying the first by 5000 we get- 23,553.5

for the second we get -6,713.6

for the third we get 41,120

adding them all together we get 71,387.1

and so C is the closest

6 0

4 years ago

Read 2 more answers

Two adjacent sides of a parallelogram are 12cm and 10cm.

-Dominant- [34]

Un parallelogramma è un quadrilatero avente i lati opposti paralleli (lato a = 10 cm, lato b = 12 cm);
La distanza tra i due lati paralleli si può considersre come l'altezza h (h=6)
L'area del parallelogramma é:
A= b×h = 12 cm × 6 cm = 72 cmq

8 0

3 years ago

What is a base of 3 with an exponent of-3??<br>

DaniilM [7]

Answer:

The answer is 1/27

Step-by-step explanation:

3^-3 can be written as 1/3^3 and 3^3 = 3x3x3= 27

Therefore, the answer is 1/27.

8 0

2 years ago

Read 2 more answers

Image is below, please help me fast i have 2 minutes left, thank you very much

Yuki888 [10]

Answer:

Step-by-step explanation:

1/3 of 90

= 1/3 * 90

= 90/3

= 30

Let the missing number be x.

2/3 of x

= 2/3 * x

= 2x/3

30 = 2x/3

Cross multiply,

2x = 30 * 3

2x = 90

x = 90/2

x = 45

Hence,

the missing number is 45.

5 0

2 years ago

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the

Paul [167]

So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem
$\bf c^2=a^2+b^2\implies \qquad 
\begin{cases}
a=2w+59\\
b=w\\
c=(2w+59)+2\to 2w+61
\end{cases}
\\\\\\
(2w+61)^2=(2w+59)^2+(w)^2
\\ \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow \\
\textit{expand using binomial theorem, or FOIL}$

you'd end up with a quadratic, after simplifying, solve for "w"

7 0

3 years ago