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bearhunter [10]
4 years ago
11

Dont mind the blue numbers. Please help!​

Mathematics
1 answer:
Jet001 [13]4 years ago
7 0

Answer:

Decrease

Increase

Increase

Decrease

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Find the surface area.
Margaret [11]

Answer:

1014cm^2

Step-by-step explanation:

find the area of one side and times it by 6 (bc a cube has 6 sides)

13×13=169

169×6=1014

6 0
3 years ago
If 0.5% of a number is 250, find the number
kaheart [24]

0.5% or 1/2% of say "x" is 250, whilst "x" is the 100%.

\begin{array}{ccll} \%&amount\\ \cline{1-2} \frac{1}{2}&250\\[1em] 100&x \end{array}\implies \cfrac{~~ \frac{1}{2}~~}{100}=\cfrac{250}{x}\implies \cfrac{1}{200}=\cfrac{250}{x}\implies x = 50000

6 0
3 years ago
Read 2 more answers
I need help on this specific equation: 10x+1=3x+9
Yuri [45]
Well, first you'd have to get the x by it's self.
10x+1=3x+9
Subtract 3x from each side and you'll have the x on only one side rather than two.
7x+1=9
Now I'd get rid of the 1 on the x's side. So just subtract 1 from each side.
7x=8
Then you should make it so the seven isn't there with the x either. Just divide each side by 7.
Answer:  x=8/7
Each time you change something on one side, you must do the same to the other side. T find the value of a variable in an equation, simple seclude it so it's on it's own without number to make things confusing.
The answer was x=8/7 btw.
3 0
4 years ago
Read 2 more answers
What is the complete factorization of 36y2 − 1?
ludmilkaskok [199]

Answer:

36y² - 1

Factorize

We have the final answer as

(y -  \frac{1}{6} )(36y + 6)

Hope this helps you

3 0
3 years ago
Suppose you want to build a fish tank in the shape of a right rectangular box with square base and no top which will hold 6 cubi
AlekseyPX
You must develop a cost function C(x) and then minimize its value.
How much dwill the glass cost?  It's $1 per sq ft, and the total area of the glass is 4(xh), where x is the length of one side of the base and h is the height of the tank.  The area of the metal bottom is x^2, which we must multiply by $1.50 per sq ft. 

This cost function will look like this:  C(x) = 4($1/ft^2)xh + ($1.50/ft^2)x^2

but we know that (x^2)h= 6 cu ft, or h = (6 cu ft) / (x^2).  Subst. this last result into the C(x) equation, immediately above:

C(x) = 4($1/ft^2)x[6 ft^3 / x^2] + ($1.50/ft^2)x^2

Let's focus on the numerical values and ditch the units of measurement for now:

C(x) = 4x(4/x^2) + 1.50x^2, or

C(x) = 16/x + 1.5x^2

Differentiate this with respect to x:

C '(x) = -16 / x^2 + 3 x

Set this equal to 0 and solve for x:    -16/x^2 = -3x, or 16 = 3x^3

Then x^3 = 16/3, and x = 5 1/3 ft.  We already have the formula  

(x^2)h= 6 cu ft, so if x = 5 1/3, or 16/3, then (16/3)^2 h = 6, or

h = 6 / [16/3]^2.

h = 6 (9/256) = 0.21 ft.  While possible, this h = 0.21 ft seems quite unlikely.


Please work through this problem yourself, making sure you understand each step.  If questions arise, or if you find an error in my approach, please let me know.

Once again:
1.  Write a formula for the total cost of the material used:  4 sides of dimensions xh each, plus 1 bottom, of dimensions x^2.  Include the unit prices:  $1 per square foot for the sides and $1.50 per square foot for the bottom.
2.  Differentiate C(x) with respect to x.
3.  Set C '(x) = 0 and solve for the critical value(s).
4.  Calculate h from your value for x.
5.  Write the dimensions of the tank:  bottom:  x^2; height:  h
4 0
4 years ago
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