Answer:
The mean weight is not greater than 16 ounces
Step-by-step explanation:
Null hypothesis: Mean weight is greater than 16 ounces
Alternate hypothesis: Mean weight is not greater than 16 ounces.
Sample mean= 16.04 ounces
Assumed mean= 16 ounces
Significance level = 0.05
Sample standard deviation = 0.08 ounces
Number of samples= 35
To test the claim about the mean, Z = (sample mean - assumed mean) ÷ (standard deviation÷ √number of samples)
Z = (16.04 - 16) ÷ (0.08 ÷ √35)
Z = 0.04 ÷ (0.08 ÷ 5.92)
Z= 0.04 ÷ 0.014 = 2.86
Z = 2.86
It is a one-tailed test, the critical region is an area of 0.05 (the significance level). The critical value of the critical region is 1.64
Since the computed Z 2.86 is greater than the critical value 1.64, the null hypothesis is rejected.
Conclusion
The mean weight is not greater than 16 ounces
2 twelve is ten more than 2. Since 2 add 10 is twelve than the answer is 2
Answer:
i think 126 different bowls
correct me if im wrong
