Please help me answer theseeeee
2 answers:
You might be interested in
Answer:
30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the Islanders win, or they do not. The probability of the Islanders winning a game is independent of other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that the islanders will beat the rangers in a game is 0.44
This means that
What is the probability that the islanders will win exactly one out of four games in a series against the rangers?
This is P(X = 1) when n = 4. Then
30.91% probability that the islanders will win exactly one out of four games in a series against the rangers
We can first add up the cards so we know how many we have in all:
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32
= 32 x 2 = 
50 x 2
= 64 : 2 = 32 %
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32
50 x 2
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.