Area of one square = 2 x 2 = 4 square feet
4 square feet x 6 squares = 24 square feet total area
Answer: 24 square feet
X + 4 is the answer to your question
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Check the picture below.
A)
well, we start off by making a table of values for the function, with a few "t" values, as you see in the picture, then graph those points to get the graph.
B)
at t = 0, h(0) = 98, and at t = 1, h(1) = 82, so it went from 98 to 82, for a difference of 16.
C)
at t = 1, h(1) = 82, and at t = 2 h(2) = 34, so it went from 82 to 34, for a difference of 48.
does it fall the same distance on both intervals? well, they're different, so nope.
For this, we need to find the area of the larger rectangle (The room) and subtract from that the area of the smaller, shaded rectangle (The rug).
A=LW (L=Length, W=Width, A=Area)
The larger rectangle first:
A=(15)(10)
A=150 feet squared
Now the Rug:
A=(12)(7)
A=84 feet squared
Now to find the area that is NOT covered by the rug, we subtract:
150-84
= 66 feet squared will NOT be covered by the rug.
Hope this Helps!
-Sinnamin
Answer:
The length of s is 5.1 inches to the nearest tenth of an inch
Step-by-step explanation:
In Δ RST
∵ t is the opposite side to ∠T
∵ r is the opposite side to ∠R
∵ s is the opposite side to ∠S
→ To find s let us use the cosine rule
∴ s² = t² + r² - 2 × t × r × cos∠S
∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°
→ Substitute them in the rule above
∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)
∴ s² = 16.81 + 50.41 - 41.1677568
∴ s² = 26.0522432
→ Take √ for both sides
∴ s = 5.10413981
→ Round it to the nearest tenth
∴ s = 5.1 inches
∴ The length of s is 5.1 inches to the nearest tenth of an inch
