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rewona [7]
4 years ago
15

Write the least common multiple of 8 and 12

Mathematics
2 answers:
hram777 [196]4 years ago
7 0
The least common multiple would be 24 :)
sukhopar [10]4 years ago
7 0
The multiples of 8 are:
8<span>, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96
The multiples of 12 are:
</span>12<span>, 24, 36, 48, 60, 72, 84, 96
</span>As we see here 12 is the least common multiple.
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X^2-10x+8=0 by completing the square
OverLord2011 [107]
When completing the square <span>x=9.12311 and </span><span>x=<span>0.876894</span></span>
4 0
3 years ago
Plz i need help What is the volume of the rectangular prism? show how you did it
Vesnalui [34]

The formula for volume is V=LWH

So in this example we have 10.4*5*8

So 8*5=40

40*10.4=416

So the volume is 416 cubic mm

Hope that helped

4 0
3 years ago
Determine points of a function that have horizontal or vertical tangent lines f(x)= (2x^3+3)/((x-1)
yan [13]
Answer:

as x tends to infinity y=infinity

as x tends to 1 y=infinity

x=1 vertical asymptote
6 0
3 years ago
What is an equation of the line that passes through the points (3,4) and (−4,−3)? Put your answer in fully reduced form
sasho [114]

Answer:

The equation of the line is y = x + 1

Step-by-step explanation:

The equation of the line is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

The rule of the slope of the line is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points on the line

∵ The line passes through points (3, 4) and (-4, -3)

∴ x1 = 3 and y1 = 4

∴ x2 = -4 and y = -3

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{-3-4}{-4-3} = \frac{-7}{-7} = 1

∴ m = 1

→ Substitute it in the form of the equation above

∴ y = 1(x) + b

∴ y = x + b

→ To find b substitute x by 3 and y by 4 in the equation

∵ 4 = 3 + b

→ Subtract 3 from both sides

∵ 4 - 3 = 3 - 3 + b

∴ 1 = b

→ Substitute it in the equation

∴ y = x + 1

∴ The equation of the line is y = x + 1

3 0
3 years ago
I NEED A ANSWER FAST PLEASE HELP
NikAS [45]

Answer:

Elevation in boiling point is mathematically expressed as

ΔTb = Kb X m

where Kb =  boiling point elevation constant =  2.53°c/m (for benzene)

m = molality of solution = 3.47 m (given)

∴ ΔTb = 2.53 X 3.47

          = 8.779 oC

But, boiling point of benzene = 80.1 oC

∴ Boiling point of solution = 88.879 oC

Now, Depression in freezing point = ΔTf = Kf X m

where, Kf = freezing point depression constant = 5.12°c/m (for benzene)

∴ ΔTf = 5.12 X 3.47

        = 17.766 oC

But freezing point of benzene = 5.5 oC

∴ Freezing point of solution = -12.266 oC

3 0
3 years ago
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