Question

I NEED A ANSWER FAST PLEASE HELP

Answer 1

Answer:

Elevation in boiling point is mathematically expressed as

ΔTb = Kb X m

where Kb =  boiling point elevation constant =  2.53°c/m (for benzene)

m = molality of solution = 3.47 m (given)

∴ ΔTb = 2.53 X 3.47

          = 8.779 oC

But, boiling point of benzene = 80.1 oC

∴ Boiling point of solution = 88.879 oC

Now, Depression in freezing point = ΔTf = Kf X m

where, Kf = freezing point depression constant = 5.12°c/m (for benzene)

∴ ΔTf = 5.12 X 3.47

        = 17.766 oC

But freezing point of benzene = 5.5 oC

∴ Freezing point of solution = -12.266 oC