Find the equation of the line that has a slope of 7 and passes through the point (-6,8).

2 answers:

7 0

Y = 7x + 50. Use slope-intercept form (y = mx + b), where m is slope, and b is the y-intercept. Insert the values we already know into the equation. y = 7x + b. Now, insert the x and y-values of your order pair into the equation and solve for b. 8 = 7(-6) + b ---> 8 = -42 + b --> 8 + 42 = -42 + b + 42 --> 50 = b or b = 50. Now that we have the value of b, insert it into the equation as well, and then you have your answer. Answer: y = 7x + 50

Bad White [126]3 years ago

6 0

Y-y1=m(x-x1)
y-8=7(x-(-6))
y-8=7(x+6)
y-8=7x+42
+8 +8
y=7x+50

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How do you answer these two questions?

-BARSIC- [3]

I think you could multiply or divide. Hope this helps:)

7 0

3 years ago

What 2 numbers multiply to be -14 and add to be -3

Svetach [21]

Xy = -14
x + y = -3

$xy = -14$
$\frac{xy}{x} = \frac{-14}{x}$
$y = \frac{-14}{x}$

$x + y = -3$
$x + \frac{-14}{x} = -3$
$\frac{x^{2}}{x} + \frac{-14}{x} = -3$
$\frac{x^{2} - 14}{x} = -3$
$x^{2} - 14 = -3x$
$x^{2} + 3x - 14 = 0$
$x = \frac{-(3) \± \sqrt{(3)^{2} - 4(1)(-14)}}{2(1)}$
$x = \frac{-3 \± \sqrt{9 + 56}}{2}$
$x = \frac{-3 \± \sqrt{65}}{2}$
$x = \frac{-3 \± 8.06}{2}$
$x = -1.5 \± 4.03$
$x = -1.5 + 4.03$ $or$ $x = -1.5 - 4.03$
$x = 2.53$ $or$ $x = -5.53$

  x + y = -3
2.53 + y = -3
- 2.53 - 2.53
  y = -5.53
  (x, y) = (2.53, -5.53)

x + y = -3
  -5.53 + y = -3
+ 5.53   + 5.53
  y = 2.53
  (x, y) = (-5.53, 2.53)

The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.

8 0

3 years ago

Given a dilation around the origin, what is the scale factor K?<br><br> Do, K = (20,16) → (-5,-4)

Rudik [331]

Answer:

Scale factor, K = -1/4

Step-by-step explanation:

Dilation of any image changes its size and the shape remains same.

The scale factor is the ratio of dilated image to original image.

Dilation rule: (x, y) → (kx, ky), where k is the scale factor.

It means k = x₂/x₁ or y₂/y₁

K = -5/20 = -1/4 or K = -4/16 = -1/4.