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juin [17]
2 years ago
8

Help me please rjdjfhdhdbdbdbdbdb

Mathematics
1 answer:
DerKrebs [107]2 years ago
6 0

Answer:

1609.1 m^{3}

Step-by-step explanation:

The area of a triangle is 1/2 base * height.

The base of one side is 13, and the height is 30.

30 * 13 = 390

390 / 2 = 195

Now, there are six of these triangle faces, so multiply that number by six.

195 * 6 = 1170

Now, just add the area of the base:

1170 + 439.1 = 1609.1

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3 years ago
How much is 3/4 of 120? And how much is 3/8 of 160?
RoseWind [281]
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3 years ago
Read 2 more answers
A truck can be rented from Company A for ​$70 a day plus ​$0.50 per mile. Company B charges ​$20 a day plus ​$0.60 per mile to r
r-ruslan [8.4K]

Answer:

The rental cost for Company A and Company B will be the same after 500 miles

Step-by-step explanation:

The total cost of renting a truck from Company A can be expressed as;

Total rental cost(Company A)=Cost per day+Total rate

where;

Cost per day=70

Total rate=rate per mile×number of miles (m)=(0.5×m)=0.5 m

replacing;

Total rental cost(Company A)=70+0.5 m...equation 1

2. The total cost of renting a truck from Company B can be expressed as;

Total rental cost(Company B)=Cost per day+Total rate

where;

Cost per day=20

Total rate=rate per mile×number of miles (m)=(0.6×m)=0.6 m

replacing;

Total rental cost(Company B)=20+0.6 m...equation 2

Equating equation 1 to equation 2

70+0.5 m=20+0.6 m

0.6 m-0.5 m=70-20

0.1 m=50

m=50/0.1

m=500 miles

The rental cost for Company A and Company B will be the same after 500 miles

7 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
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