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2 years ago

8

Help me please rjdjfhdhdbdbdbdbdb

1 answer:

DerKrebs [107]2 years ago

6 0

Answer:

$1609.1 m^{3}$

Step-by-step explanation:

The area of a triangle is 1/2 base * height.

The base of one side is 13, and the height is 30.

30 * 13 = 390

390 / 2 = 195

Now, there are six of these triangle faces, so multiply that number by six.

195 * 6 = 1170

Now, just add the area of the base:

1170 + 439.1 = 1609.1

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This question has three parts. Answer the parts in order.

nalin [4]

Answer:

The area of the smallest section is $A_{1}=100yd^{2}$

The area of the largest section is $A_{2}=625yd^{2}$

The area of the remaining section is $A_{3}=250yd^{2}$

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

$A_{1}=10yd*10yd$

$A_{1}=100yd^{2}$

- Area of the second section:

$A_{2}=x^{2}$ (Eq.1)

- Area of the third section:

$A_{3}=width*length$

$A_{3}=10yd*x$ (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

$A_{1}+A_{2}+A_{3}=975yd^{2}$

Replacing values:

$100+x^{2}+10x=975$

Solving for x:

$x^{2}+10x-875=0$

$x=\frac{-10+\sqrt{100+(4*875)}}{2}$

$x=\frac{-10+\sqrt{3600}}{2}$

$x=\frac{-10+60}{2}$

$x=25$

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

$A_{2}=25^{2}$

$A_{2}=625yd^{2}$

- From Eq.2:

$A_{3}=10*25$

$A_{3}=250yd^{2}$

3 0

2 years ago

You need to buy some chicken for dinner tonight. You found an ad showing that the store across town has it on sale for $2.79 a p

san4es73 [151]

Answer:

B) Going to the close store is cheaper.

Step-by-step explanation:

Cost of going to the next town:

(8.3mi/22mi) × $3.79 = $1.43

Cost of going to the close store:

(2.3mi/22mi) × $3.79 = $0.40

3 0

2 years ago

Which of the numbered stones shown cannot be mapped to another with a rigid motion?

Andreas93 [3]

Answer:

7,8,11,12,13,14

8 0

2 years ago

(a) Find an angle between 0 and 2π that is coterminal with −19π10.

Katarina [22]

Answer:

$\dfrac{\pi}{10}$ .

Step-by-step explanation:

All coterminal angles of an angle $\theta$ are defined as

$\theta +2n\pi$ or $\theta + n360^{\circ}$

where, n is an integer.

The given angle is

$\theta=-\dfrac{19\pi}{10}$

So, all coterminal angles of an angle $\theta$ are

$-\dfrac{19\pi}{10}+2n\pi$

For n=1,

$\Rightarrow -\dfrac{19\pi}{10}+2(1)\pi$

$\Rightarrow -\dfrac{19\pi}{10}+2\pi$

$\Rightarrow \dfrac{-19\pi+20\pi}{10}$

$\Rightarrow \dfrac{1\pi}{10}$

Since, $\dfrac{\pi}{10}$ between 0 and 2π, therefore, the required coterminal angle is $\dfrac{\pi}{10}$ .

6 0

2 years ago

30 POINTS PLEASE HELP

chubhunter [2.5K]

Answer:

y = 4x + 17

Step-by-step explanation:

y = mx + b given points: (-3,5) (-5,-3)

$\frac{5+3}{-3+5}$ = $\frac{8}{2}$ = 4

y = 4x + 17

5 0

2 years ago

Read 2 more answers