Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
Step-by-step explanation:
to calculate mean add all the entries in a week ,then divide by 7(the number of days)
i give you hint
mean for week 1=(52+65+... +60)/7
Factor the polynomial:
4u² – 20u + 25
Rewrite – 20u as – 10u – 10u, and then factor it by grouping:
= 4u² – 10u – 10u + 25
= 2u * (2u – 5) – 5 * (2u – 5)
= (2u – 5) * (2u – 5)
= (2u – 5)² <––– this is the answer.
I hope this helps. =)
<h2>It's <u>1849</u></h2>
I'll explain how I found it without actual multiplication,
So,
Hope this will help....
