Question

Determine the intercepts of the line Y+1=3(x-4)

Answer 1

Answer:

x-intercept = $\frac{13}{3}$

y-intercept = $-13$

Step-by-step explanation:

We are given the following equation of a line and we are to find the x and y intercepts for it:

$y + 1 = 3 ( x - 4 )$

In order to find the x-intercept, we will substitute 0 in place of y to get:

$0 + 1 = 3 ( x - 4 ) \\\\ 1 = 3 x - 12 \\\\ 3 x = 1 + 12 \\\\ x = \frac { 13 } { 3 }$

And to find the y-intercept, we need to substitute 0 in place of x:

$y + 1 = 3 ( 0 - 4 ) \\\\ y + 1 = -124 \\\\ y = - 12 - 1 \\\\ y = - 13$

So the x-intercept is $\frac{13}{3}$ while the y-intercept is $-13$.

Answer 2

ANSWER

y-intercept:

(0,-13)

x-intercept:

$(4 \frac{1}{3} ,0)$

EXPLANATION

The given line has equation

$y + 1 = 3(x - 4)$

At y-intercept , x=0.

This implies that;

$y + 1 = 3(0 - 4)$

$y = - 12 - 1$

$y = - 13$

The y-intercept is

(0,-13).

At x-intercept y=0,

This implies that;

$0+ 1 = 3(x - 4)$

$\frac{1}{3} = x - 4$

$\frac{1}{3} + 4 = x$

$4 \frac{1}{3} = x$

The x-intercept is

$(4 \frac{1}{3} ,0)$