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SIZIF [17.4K]
2 years ago
8

The polynomial 2x3 − 5x2 + 4x − 10 is split into two groups, 2x3 + 4x and −5x2 − 10. The GCFs of each group is then factored out

.
What is the common binomial factor between the two groups after their GCFs have been factored out?

a)2x + 5
b)2x − 5
c)x2 − 2
d)x2 + 2
Mathematics
2 answers:
Phoenix [80]2 years ago
5 0

Answer:

2x³ - 5x² + 4x - 10

(2x³ + 4x) + (-5x² - 10)

2x(x² + 2) - 5(x² + 2) = Answer is Choice D. Step-by-step explanation:

Marrrta [24]2 years ago
4 0
2x³ - 5x² + 4x - 10

(2x³ + 4x) + (-5x² - 10)

2x(x² + 2) - 5(x² + 2) = Answer is Choice D. x² + 2
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Plz help me get the answer to these
Pavlova-9 [17]

Remove the brackets

-5a + 9b + 7a               combine -5a and 7a

7a - 5a + 9b

2a + 9b                        Answer

Don't go any further. There is nothing else to do. These are unlike terms and cannot be reduced or combined.

8 0
3 years ago
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He vertices of ?ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ?ABC is units, and its area is square units.
iogann1982 [59]

Answer:

Note :

The perimeter is :  AB + BC + CA


AB =√((XB - XA)² + (YB - YA)²) = √((16-2)²+(2-8)²) = √(12²+6²) = √(144+36)=√180

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8 0
2 years ago
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Is this a 3-4th fraction
mezya [45]

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The clock hand made a 90 degree turn. It is not a 3/4 fraction.

7 0
3 years ago
HELP AGAIN :))) PLEASE HELP
Zielflug [23.3K]

Answer:

55

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4 0
3 years ago
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Points b d and f are midpoints of ten sides of ace ec=44 df=25 find ac
scZoUnD [109]

Answer:

The length of AC is;

C. 50

Step-by-step explanation:

By the midpoint of a triangle theorem, we have that a segment that spans across and intersects with the midpoints of two sides of a triangle is equal to half the length of the third side and parallel to the length of the third side

The given parameters are;

The midpoints of ΔACE are B, D, and F

The length of EC = 44

The length of DF = 25

Therefore, we have;

Given that DF is a midsegment of triangle ΔACE, then DF ║ AC and

the length of DF = (1/2) × AC the length of AC

∴ The length of AC = 2 × The length of DF

The length of DF = 25

∴ The length of AC = 2 × 25 = 50

The length of AC = 50

4 0
2 years ago
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