A priter charges $2.85 for binding plus 10 cents per pages for each copy of a community group's annual report. If the report cos
1 answer:
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Answer:
y = 2
Step-by-step explanation:
The mid segment HJ is half of the third side GK , that is
HJ = GK , substitute values
2y = (y + 6) ← multiply both sides by 2 to clear the fraction
4y = y + 6 ( subtract y from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer:
The volume of the ball with the drilled hole is:
Step-by-step explanation:
See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:
Then we set the integral for the volume by using shell method:
That can be solved by substitution:
The limits of integration also change:
For x=5:
For x=15:
So the integral becomes:
If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:
Then applying the basic rule we get:
Since that is just half of the solid, we multiply by 2 to get the complete volume:
