1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
7

please help me I have a lot more I need help on or I will fail this semester of college so please help me!!!

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

We cant see none bro or sis we dont judge here

You might be interested in
Does the expression 1.016x represent a percent increase greater than 12% if the original amount is x? How could I rewrite the ex
GrogVix [38]

Answer:

The expression 1.016x does not represent a percent increase greater than 12%.

Step-by-step explanation:

We are asked to find whether the expression 1.016x represent a percent increase greater than 12% if the original amount is x.

First of all, we will find 12% increase. The total amount after x% increase would be original amount plus 12% of original amount.

\text{12 percent increase}=x+\frac{12}{100}x

\text{12 percent increase}=x+0.12x    

\text{12 percent increase}=1.12x

Since 1.12 is greater than 1.016, therefore, the expression 1.016x does not represent a percent increase greater than 12%.

We can rewrite 1.016x as:

1.016x=1x+0.016x=x+0.016x

Let us convert 0.016 to percent by multiplying by 100.

0.016\times 100\%=1.6\%

Since 1.6% is less than 12%, therefore, the expression 1.016x does not represent a percent increase greater than 12%.

4 0
4 years ago
Please help me on this and I will give you BRIANLEIST Thank You ^ ^
dalvyx [7]

Answer:

the answer is five

5 0
3 years ago
Read 2 more answers
#18-4: Douglas invests $550 in high-yield savings account. The account pays 2.1% simple interest annually. If he doesn't add or
kap26 [50]

Answer:

No

Step-by-step explanation:

You want to calculate the interest on $550 at 2.1% interest per year after 4 years.

The formula we'll use for this is the simple interest formula, or:

I = P x r x t

P is the principal amount, $550.00.

r is the interest rate, 2.1% per year, or in decimal form, 2.1/100=0.021.

t is the time involved, 4 years.

So, t is 4 year time periods.

To find the simple interest, we multiply 550 × 0.021 × 4 to get that:

The interest is: $46.20

3 0
3 years ago
I need help what is this solution
viva [34]
X/6 is simplest expression
7 0
3 years ago
Read 2 more answers
How do you do this I’ve been stuck on this
Mamont248 [21]

9514 1404 393

Answer:

  x^(1/6)

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

__

Here, we have a=X, b=1/2, c=1/3, so the quotient is ...

  (X^(1/2))/(X^(1/3)) = X^(1/2 -1/3) = X^(1/6)

_____

Expressed as a radical, this is ...

  \displaystyle X^{\frac{1}{6}}=\sqrt[6]{X}

4 0
3 years ago
Read 2 more answers
Other questions:
  • In a survey of 225 art students 28% reported that their favorite color is blue. What is the margin of error for the sample?
    9·1 answer
  • A spinner is divided equally into four colors, red, green, yellow and blue. Find the sum of the probabilities of spinning red, g
    10·1 answer
  • Error Analysis: Kayla said the remainder of x^3+ 2x^2 -4x + 6 divided by
    10·1 answer
  • A bag of M&M's has 6 red, 5 green, 4 blue, and 8 yellow M&M's. What is the probability of randomly picking: (give answer
    12·2 answers
  • Hey Please help me with these two questions! TYSM!
    12·2 answers
  • In PRS below, m<br>48<br>84<br>90<br>96<br><br>I NEEED HELP!!!
    12·1 answer
  • Use the equation s=5q+8 to find the value of s when q=1.
    13·1 answer
  • Multiply.<br><br> (3x+2)(2x−5)<br><br><br> 6x^2+4x−3<br> 6x^2−10<br> 6x^2−11x−10<br> 6x^2−13x−3
    15·1 answer
  • Which expression is equivalent to....​
    12·2 answers
  • QUESTIONS BELOW! PLEASE HELP DONT KNOW WHERE TO START IM CONFUSED AND NEED THIS DONE!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!