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brilliants [131]
3 years ago
15

Rashad is having a picnic for 62 guests. He plans to serve each guest at least one hamburger. If each package, p, contains eight

hamburgers, write the inequality that could be used to determine how many packages of hamburgers Rashad will need to buy.
Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

Are you in connections academy to X3

I personally got 8p(the more than or equal to sign) 62

i could be wrong cause i dont know it either

You might be interested in
2^5×5×11 and 2^3×5^2×7​
IceJOKER [234]

Answer:

1. 1760

2. 1400

Step-by-step explanation:

2^5 = 32

32 × 5 = 160

160 × 11 = 1760

2^3 = 8

5^2 = 25

8 × 25 = 200

200 × 7 = 1400

4 0
3 years ago
Find the correct values for the variables that make the statement cos(h)=x/y true.
Stels [109]

Answer:

The sum of the measures of the angles in a triangle is equal to 180 degree.

In triangle FGH;

\angle F + \angle G + \angle H = 180^{\circ}

or

\angle H = 180^{\circ} -{\angle F + \angle G}

Substitute the given values from the given figure we have;

\angle H = 180^{\circ} -{33^{\circ} + 90^{\circ}}

\angle H = 180^{\circ} -{123^{\circ}}

Simplify:

\angle H = 57^{\circ}

Given that:

\cos H = \frac{x}{y}

Using Cosine ratio:

\cos \theta = \frac{\text{Base}}{\text{Hypotenuse}}

In a given figure:

Base = GH = x and Hypotenuse = FH = y = 80 cm

Then;

\cos 57^{\circ}= \frac{x}{80}

or

x = \cos 57^{\circ} \cdot 80  

x = 0.54463903501 \cdot 80 \approx 43.57 cm

Therefore, the value of :

H = 57^{\circ}

x = 43.57 cm

y = 80 cm





5 0
3 years ago
Read 2 more answers
When f(x) = 4x + 1 and g(x) = 4x - 3<br> Find f(x) * g(x)<br> Pls need help can u answer these ?
earnstyle [38]

Answer:

(4x+1)(4x-3)

4x(4x-3)+1(4x-3)

16x²-12x+4x-3

16x²-8x-3

6 0
3 years ago
Answer 396,397,398,399
ololo11 [35]

Answer:

yes you are right I think

6 0
1 year ago
What is the value of b^2 - 4ac for the following equation? <br><br> 2x^2 + 3x = -1
Shtirlitz [24]
Hello :
2x²+3x+1=0
a=2     b=3    c=1
b²-4ac = (3)²-4(2)(1) = 1
6 0
3 years ago
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