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Rus_ich [418]
3 years ago
10

54 divided by 6=0.09

Mathematics
2 answers:
Travka [436]3 years ago
6 0
No that answer is wrong it is 8
Stolb23 [73]3 years ago
3 0
No, it's just 9. No decimal.
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For the following right triangle, find the side length x. around your answer to the nearest hundredth
ella [17]
≈9.38

13² - 9² = x²
189 - 81 = 88
√88 = x
6 0
3 years ago
Can someone help solve for X
Morgarella [4.7K]

Answer:

x = 2sqrt(5)

Step-by-step explanation:

We can use the Pythagorean theorem to solve

The legs are x and 8/2 =4

and the hypotenuse is 6

a^2 + b^2 = c^2

x^2 +4^2 = 6^2

x^2 +16 = 36

Subtract 16 from each side

x^2 +16-16=36-16

x^2 = 20

Take the square root of each side

sqrt(x^2) = sqrt(20)

x = sqrt(4*5)

x = sqrt(4) sqrt(5)

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5 0
3 years ago
Read 2 more answers
Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
HELP PLS HELPIf the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from
Y_Kistochka [10]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Please help!! Very urgent..thank you!!
erastova [34]

Answer : 4 times

Here it's given that ,

  • The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .

And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .

Let us take ,

  • base of blue butterfly be b
  • height of blue butterfly be h
  • Area be A .

Then ,

  • base of red butterfly will be 2b .
  • height of red butterfly will be 2h .
  • Area be A' .

We know that ,

→ area of the triangle = 1/2 × base × height

So that ,

→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)

→ A/A' = bh/4bh

→ A/A' = 1/4

→ A' = 4A

<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>

I hope this helps.

6 0
2 years ago
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