Please help!! Very urgent..thank you!!
1 answer:
Answer : 4 times
Here it's given that ,
The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .
And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .
Let us take ,
base of blue butterfly be b height of blue butterfly be h Area be A .
Then ,
base of red butterfly will be 2 b . height of red butterfly will be 2 h . Area be A' .
We know that ,
→ area of the triangle = 1/2 × base × height
So that ,
→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)
→ A/A' = bh/4bh
→ A/A' = 1/4
→ A' = 4A
<u>Henceforth</u> <u> the</u> <u> area</u> <u> of</u> <u> </u> <u>blue</u> <u> butterfly</u> <u> is</u> <u> </u> <u>4</u> <u> </u> <u>times </u> <u>greater</u> <u> than</u> <u> </u> <u>that</u> <u> of</u> <u> </u> <u>red </u> <u>winged</u> <u> butterfly</u> <u> </u> <u>.</u>
I hope this helps.
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