260 quarts * 36 hours = 9,360 quarts
260 * 20 hours = 5,200 quarts ---> 260 quarts / 10 hours = 26 quarts per hour ---> 26 quarts * 4= 104 quarts ---> 5,200 + 104 = 5,304 quarts per day
Answer:
16
Step-by-step explanation:
as an expression: (15 - 6) + (-2 + 9)
simplify quantities: (9) + (7)
sum: 16
:D
Answer:
slope = 1
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (- 1, 0)
m =
=
= 1
cost of one peppermint cookies = $ 0.6
cost of one cinnamon sugar cookies = $ 0.3
<h3><u>Solution:</u></h3>
Let "p" be the cost of one peppermint cookies
Let "c" be the cost of one cinnamon sugar cookies
<u><em>To find: cost of each cookie</em></u>
<h3><u><em>
On the first day, they sold 120 peppermint cookies and 30 cinnamon sugar cookies for a total of $81</em></u></h3>
We can frame a equation as:
120 peppermint cookies x cost of one peppermint cookies + 30 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120p + 30c = 81 --------- eqn 1
<h3><u><em>
The next day they made $60 by selling 70 peppermint cookies and 60 cinnamon sugar cookies</em></u></h3>
70 peppermint cookies x cost of one peppermint cookies + 60 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70p + 60c = 60 --------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "p" and "c"
Multiply eqn 1 by 2
240p + 60c = 162 --- eqn 3
Subtract eqn 2 from eqn 3
240p + 60c = 162
70p + 60c = 60
(-) -------------------------
170p = 102
<h3>p = 0.6</h3>
Substitute p = 0.6 in eqn 1
120p + 30c = 81
120(0.6) + 30c = 81
72 + 30c = 81
30c = 9
<h3>c = 0.3</h3>
<u><em>Summarizing the results:</em></u>
<em>cost of one peppermint cookies = $ 0.6</em>
<em>cost of one cinnamon sugar cookies = $ 0.3</em>
Answer:
21 hours
Step-by-step explanation:
You want to find x such that B(x) = 31. Fill in the value and solve.
... 31 = 1.33e^(0.15x)
... 31/1.33 = e^(0.15x) . . . . divide by 1.33
... ln(31/1.33) = 0.15x . . . . take the natural log
... ln(31/1.33)/0.15 = x ≈ 20.992 . . . . hours
After 21 hours, the concentration will be 31 M/mL.