Debra drove 737 miles in 11 hours.
1 answer:
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Answer:
5040,56
Step-by-step explanation:
We have to construct pass words of 4 digits
a) None of the digits can be repeated
We have total digits as 0 to 9.
4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)
No of passwords = 10P4
=
b) start with 5 and end in even digit
Here we restrain the choices by putting conditions
I digit is compulsorily 5 and hence only one way
Last digit can be any one of 0,2,4,6,8 hence 5 ways
Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)
=56
To solve for r, you would start by subtracting p from both sides.
2m - p = -q/r
Multiply everything by r.
2mr - pr = -q
Factor r out of the left side of the equation.
r(2m - p) = -q
Divide both sides by (2m - p).
r = .