What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) What is the area of the rectangle?
1 answer:
Answer:
The area of the triangle with the given vertices is 10 square units
Step-by-step explanation:
x y
D 3 3
E 3 -1
F -2 -5
D 3 3
Area: A=Abs [(xd ye + xe yf + xf yd) - (yd xe + ye xf + yf xd)] /2
Absolute value: Abs
A = Abs { [(3)(-1)+(3)(-5)+(-2)(3)] - [(3)(3)+(-1)(-2)+(-5)(3)] } / 2
A = Abs [ (-3-15-6)-(9+2-15) ] / 2
A = Abs [ (-24)-(-4) ] / 2
A = Abs ( -24+4) / 2
A = Abs (-20) / 2
A = 20 / 2
A = 10 square units
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