What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) What is the area of the rectangle?
1 answer:
Answer:
The area of the triangle with the given vertices is 10 square units
Step-by-step explanation:
x y
D 3 3
E 3 -1
F -2 -5
D 3 3
Area: A=Abs [(xd ye + xe yf + xf yd) - (yd xe + ye xf + yf xd)] /2
Absolute value: Abs
A = Abs { [(3)(-1)+(3)(-5)+(-2)(3)] - [(3)(3)+(-1)(-2)+(-5)(3)] } / 2
A = Abs [ (-3-15-6)-(9+2-15) ] / 2
A = Abs [ (-24)-(-4) ] / 2
A = Abs ( -24+4) / 2
A = Abs (-20) / 2
A = 20 / 2
A = 10 square units
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3x - y = 0 . . . (1)
5x + 2y = 22 . . . (2)
From (1), y = 3x . . . (3)
Putting (3) into (2) gives:
5x + 2(3x) = 22
5x + 6x = 22
11x = 22
x = 2
From (3), y = 3(11) = 33
x = 11, y = 33.
Answer:
hello the function graph is turned 90 degree like clock way.
The answer to your question is D
Answer:
131
Step-by-step explanation:
Answer:
60cm
Step-by-step explanation:
the length of other side = sqrt (square root) hypotenuse^2 - the length of thrid side^3 = sqrt 61^2 - 11^2 = sqrt 60^2 = 60
