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3 years ago

Please help me Im confused on this problem

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

b = 6 sqrt(2)

Step-by-step explanation:

Since this is right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

3^2 + b^2 = 9^2

9+b^2 = 81

b^2 = 81-9

b^2 = 72

Take the square root of each side

sqrt(b^2) = sqrt(72)

b = sqrt(36*2)

b = 6 sqrt(2)

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PLEASE ANSWER! Given the functions f(x) = x2 + 6x - 1, g(x) = -x2 + 2, and h(x) = 2x2 - 4x + 3, rank them from least to greatest

Ratling [72]

Answer:

he rank from least to great based on their axis of symmetry:

0, 1, -3 ⇒ g(x), h(x), f(x)

So, option C is correct.

Step-by-step explanation:

A quadratic equation is given by:

$ax^2+bx+c =0$

Here, a, b and c are termed as coefficients and x being the variable.

Axis of symmetry can be obtained using the formula

$x = \frac{-b}{2a}$

Identification of a, b and c in f(x), g(x) and h(x) can be obtained as follows:

$f(x) = x^2 + 6x - 1$

⇒ a = 1, b = 6 and c = -1

$g(x) = -x^2 + 2$

⇒ a = -1, b = 0 and c = 2

$h(x) = 2^2 - 4x + 3$

⇒ a = 2, b = -4 and c = 3

So, axis of symmetry in $f(x) = x^2 + 6x - 1$ will be:

$x = \frac{-b}{2a}$

x = -6/2(1) = -3

and axis of symmetry in $g(x) = -x^2 + 2$ will be:

$x = \frac{-b}{2a}$

x = -(0)/2(-1) = 0

and axis of symmetry in $h(x) = 2^2 - 4x + 3$ will be:

$x = \frac{-b}{2a}$

x = -(-4)/2(2) = 1

So, the rank from least to great based on their axis of symmetry:

0, 1, -3 ⇒ g(x), h(x), f(x)

So, option C is correct.

Keywords: axis of symmetry, functions

Learn more about axis of symmetry from brainly.com/question/11800108

#learnwithBrainly

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