The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
Answer:
Comparing each pair of lines,
AB and EF,
BC and FG,
CD and GH,
DA and HE.
For, AB and EF,
If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.
Also, we can use the formula, for the distance between two points on a coordinate plane,
,
As we can see in the image,
A = (-1, 1),
B = (-3, 2),
C = (-4, 4),
D = (-2, 6),
E = (2, 0),
F = (4, 1),
G = (5, 3),
H = (3, 5),
Solving using the formula,
AB = EF = √5,
BC = FG = √5,
CD = GH = √8,
DA = HE = √26,
Therefore, the length of all the sides of the polygon are the same,
Hence, the two figures are congruent.
Step-by-step explanation:
Answer:
X=-3
Step-by-step explanation:
5x - 9
-2x + 12
(+) (-)
7x = -21
X= -3
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There are 400 candies in the machine.
Step-by-step explanation:
Given,
Number of red candies in machine = 104
This represents 26% of the total candies.
Let,
x be the total candies in the machine.
According to statement;
26% of x = 104

Dividing both sides by 0.26

There are 400 candies in the machine.
Keywords: percentage, division
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Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C