Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
yes, it does not matter if the y is at the beginning or at the end. However, most teachers usually prefer to have the y at the beginning as it is easier to read.
The Median is the middle value.
Arrange the numbers in order from smallest to largest:
Seattle: 23.78 , 32.46, 40.30, 45.79, 49.42, 55.14
Since there is an even number, the median is found by adding the 2 middle numbers and dividing by 2.
Median for Seattle: 40.30 + 45.79 = 86.09 / 2 = 43.045
Now do the same for Las Vegas:
2.33, 3.72, 3.84, 4.11, 5.62, 8.79
Median for Las Vegas: 3.84 + 4.11 = 7.95 / 2 = 3.975
Difference: 43.045 - 3.975 = 39.07
The answer is B.
Answer:
8h+100
8.50h+80
Step-by-step explanation:
Answer:
i wish i could help. im so bad at math
Step-by-step explanation: good luck
