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Alik [6]
3 years ago
15

What is −58÷910 ? −2536 −916 −3580 −136

Mathematics
2 answers:
aleksley [76]3 years ago
5 0
It is -0.063 when dividing -58/910

ziro4ka [17]3 years ago
3 0
Im not sure the question. negative 58 divided by 910 is -0.0637, but that isnt an answer choice.
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Pls help, will mark brainliest
SashulF [63]

Step-by-step explanation:

\frac{\pi}{2}  = 90

its 1/4 of the circle

circle circumference:

8 \times \pi

we need 1/4 of it, so its

2 \times \pi = 6.28

5 0
3 years ago
Anyone do Connections Academy???<br><br> just wanna know.-.
Contact [7]

Answer: no but some people do

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
10 points need help asap
alexandr402 [8]

Answer:

Cross section is the term name given to the front of any prism. SO, they are only found in a prism. They are recognized as the side/face that appears twice in a prism, and the shape have a visible length between these 2, known as the height

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Which equivalent fractions can you use to find the sum of 2/8 + 3/9?
sattari [20]
You can you 72 which would make 2/8 18/72 and 3/9 24/72 which makes the sum 42/72.
7 0
3 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
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