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2 years ago

Use words to explain how to multiply (33)(34).

Mathematics

1 answer:

Setler [38]2 years ago

4 0

Answer:

The answer is 1122.

Step-by-step explanation:

First, multiply 34 by 3. That gives you 102.

Then multiply 34 by 3 again. But when you're writing this down in calculations, put a zero in the ones column then write your answer. (I'll show an example of what this looks like at the bottom.

Then, add your answers and you'll have your answer...

Click on the link.

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Ningbo Shipping has issued preferred stock at its $125 per share par value. The stock will pay a $15 annual dividend. The cost o

katen-ka-za [31]

Answer:

The cost of Ningbo Shipping Preferred stock is 12.40%

Step-by-step explanation:

In this question, we are asked to calculate the cost of Ningbo shipping Preferred stock.

To calculate this, we make use of the following mathematical relation;

The cost preferred stock Kp = Annual dividends/ Issued price-Cost of Issuing

From the question, we identify the following;

Issued price = $125

Annual dividend = $15

Cost of Issuing = $4

Inserting these into the formula we have;

Kp = $15/$125 - $4 = 12.40%

This means that Cost of Ningbo shipping preferred stock is 12.40%

5 0

2 years ago

Can anyone help me integrate :

worty [1.4K]

Rewrite the second factor in the numerator as

$2x^2+6x+1=2(x+2)^2-2(x+2)-3$

Then in the entire integrand, set $x+2=\sqrt3\sec t$ , so that $\mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt$ . The integral is then equivalent to

$\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt$
$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt$

Note that by letting $x+2=\sqrt3\sec t$ , we are enforcing an invertible substitution which would make it so that $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ requires $0\le t$ or $\dfrac\pi2$ . However, $\tan t$ is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which $\tan t>0$ so that $|\tan t|=\tan t$ . This allows us to write

$=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt$
$=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt$

We can show pretty easily that

$\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C$
$\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C$
$\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C$

which means the integral above becomes

$=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C$
$=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C$

Back-substituting to get this in terms of $x$ is a bit of a nightmare, but you'll find that, since $t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}$ , we get

$\sec t=\dfrac{x+2}{\sqrt3}$
$\sec^2t=\dfrac{(x+2)^2}3$
$\tan t=\sqrt{\dfrac{x^2+4x+1}3}$
$\cot t=\sqrt{\dfrac3{x^2+4x+1}}$
$\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}$
$\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}$

etc.

3 0

2 years ago

Find the measure of b. (Explain how you found it please!)

Allisa [31]

Answer:

125 deg

Step-by-step explanation:

Keep these three rules in mind:

1) A central angle (vertex is the center of the circle) has the same measure as the arc it intercepts.

2) The measure of an inscribed angle (vertex is point on circle) is half the measure of the intercepted arc.

3) Opposite angles of a rectangle inscribed in a circle are supplementary.

110 deg is a central angle.

By rule 1), the arc intercepted by the central angle 110 deg also measures 110 deg.

a is an inscribed angle that intercepts an arc of 110 deg.

By rule 2), the measure of an inscribed angle is half the measure of the intercepted arc.

angle a measures 55 deg.

Rule 3) Angles a and b are supplementary.

a + b = 180

55 + b = 180

b = 125

5 0

2 years ago

Alice invests $5,000 at age 28 from the signing bonus of her new job. She hopes the investments will be worth $20,000 when she t

dolphi86 [110]

Answer:4000 per year

Step-by-step explanation:

6 0

2 years ago

What is the relative minimum of the function?<br><br> Enter your answer in the box.

trapecia [35]

Answer:

-5

Step-by-step explanation:

The minimum is at the vertex. This is at (1, -5)

The minimum value is -5

5 0

2 years ago