Step-by-step explanation:
Thats the answer it's easy
Answer:
40 units
Step-by-step explanation:
A=hbb
2=8·10
2=40
Answer:
1/5
Step-by-step explanation:
The slope of a line at any given point is Rise/run
If I start at Point (0,2) and go to point (5,3)
I have to Rise 1 point up.
I go across, or run, 5.
1/5
so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant
![\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx%7D%7B9%7D~~%2C~~%5Cstackrel%7By%7D%7B-3%7D%29%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bhypotenuse%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B9%5E2%2B%28-3%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B81%2B9%7D%5Cimplies%20c%3D%5Csqrt%7B90%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Let's solve your equation step-by-step.<span><span><span><span><span><span>2<span>x4</span></span>−<span>7<span>x3</span></span></span>+<span>4<span>x2</span></span></span>+<span>7x</span></span>−6</span>=0</span>Step 1: Factor left side of equation.<span><span><span><span><span>(<span>x+1</span>)</span><span>(<span>x−1</span>)</span></span><span>(<span>x−2</span>)</span></span><span>(<span><span>2x</span>−3</span>)</span></span>=0</span>Step 2: Set factors equal to 0.<span><span><span><span><span>x+1</span>=<span><span><span>0 or </span>x</span>−1</span></span>=<span><span><span>0 or </span>x</span>−2</span></span>=<span><span><span>0 or </span><span>2x</span></span>−3</span></span>=0</span><span><span><span><span>x=<span>−<span><span>1 or </span>x</span></span></span>=<span><span>1 or </span>x</span></span>=<span><span>2 or </span>x</span></span>=<span>32</span></span>Answer:<span><span><span><span>x=<span>−<span><span>1 or </span>x</span></span></span>=<span><span>1 or </span>x</span></span>=<span><span>2 or </span>x</span></span>=<span>3<span>2</span></span></span>
