The four stages of cellular respiration do not function independently. Instead, they ________
1 answer:
<u>Answer: </u>
Four stages involved in cellular respiration does not function independently. Instead, they Dependent on each other.
<u>Explanation:</u>
Four stages in cellular respiration involves Glycolysis, link reaction, Kerbs cycle, electron transport chain.
Glycolysis is the initial stage in cellular respiration. In this stage, the glucose present in the cytoplasm is broken down into 2 molecules of Pyruvate.
The second stage is the link reaction or the bridge reaction. In this stage, the pyruvate produced in the first stage is pumped actively into the mitochondria. Now the pyruvate is converted into acetyl group by removing one molecule of and two molecules of
. This acetyl group combines with CoA Enzyme to produce acetyl CoA.
In the Kerb’s Cycle, the Acetyl CoA combines with oxaloacetate to form a 6 carbon atom compound.
Now in the electron transport chain stage, the energy released by the electrons are used to pump the hydrogen that was removed in the previous stages.
Thus the by-product of one stage is used as the source in another stage. Hence the cellular respiration process is not independent.
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Answer:
by testcrossing with a homozygous recessive partner
Explanation:
<u>If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.</u>
Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.
The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.
When B_ is crossed with bb:
B_ x bb
Progeny
2 Bb
2 _b
The phenotype of Bb would be brown (since B is dominant over b) while the phenotype of _b would depend on the zygosity level of the cockroach.
If the unknown genotype is BB, then _b becomes Bb and the phenotype will be a brown body. This means that all the progeny will appear brown. (<em>see the first attached image for the Punnet's square</em>)
In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (<em>attached</em>
