Let the point be P, and the masses be located at P1 and P2.
The centre of mass is such that the moments of masses m1 and m2 exert an equal moment at the point P,
and the distance P1P2=d
namely,
m1(mPP1)=m2(mPP2)
The distance of the centre of mass from m1 is therefore
d1=d*m2/(m1+m2)
Similarly, the distance of the centre of mass from m2 is
d2=d*m1/(m1+m2)
Answer:
<h2>D. Quadrant III</h2>
Step-by-step explanation:
Quadrant in coordinate geometry is divided into four parts which is called Quadrants.
Quadrants I (x, y)
Quadrants II (-x, y)
Quadrants III (-x, -y)
Quadrants IV (x, -y)
so W(-3, -9) both are negatives so its lie on Quadrants III
Ur answer would be: 3/4. In decimal form it would be 0.75.
Answer:
The sum of exterior angles in a polygon is always equal to 360 degrees. Therefore, for all equiangular polygons, the measure of one exterior angle is equal to 360 divided by the number of sides in the polygon. an exterior angle.
<h3>hope it's help you </h3><h3>plz mark as brain list .....!!!!!!!!!!</h3>
