First, we know that y is equal to -8x, so we can move the -8x to replace y in the first equation, then in the first equation we get -8x=6x-14, subtract 6x on both sides, -14x=-14, x=1

4 0

3 years ago

the verticales of triangle XYZ are X(-3,-6),Y(21,-6),and Z(21,4). What is the perimeter of the triangle

andrezito [222]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

X(-3, -6), Y(21, -6). Substitute:

$XY=\sqrt{21-(-3))^2+(-6-(-6))^2}=\sqrt{24^2+0^2}=\sqrt{24^2}=24$

X(-3, -6), Z(21, 4). Substitute:

$XZ=\sqrt{(21-(-3))^2+(4-(-6))^2}=\sqrt{24^2+10^2}=\sqrt{576+100}=\sqrt{676}=26$

Y(21, -6), Z(21, 4). Substitute:

$YZ=\sqrt{(21-21)^2+(4-(-6))^2}=\sqrt{0^2+10^2}=\sqrt{10^2}=10$

The perimeter of the triangle XYZ:

$P_{\triangle XYZ}=XY+XZ+YZ$

Substitute:

$P_{\triangle XYZ}=24+26+10=60$

6 0

3 years ago