9514 1404 393
Answer:
6
Step-by-step explanation:
The value of b that makes the two lines identical is the opposite of the y-intercept of the line.
y = 6x -6 . . . . has y-intercept = -6
The value of b is the number in the term -6, so is 6.
Let's let
<u>x = the number of chef salads, x>=0</u>
<u>y = the number of Caesar salads, y>=0</u>
The constrains are:
40 <= x <= 60
35 <= y <= 50
x + y <= 100
The objective function here is F(x, y) = 0.75x + 1.20y
The corner points are (40, 35), (60, 35), (60, 40), (50, 50) and (40, 50).
F (40, 35) = 0.75*40 + 1.20*35 = $72
F (60, 35) = 0.70*60 + 1.20*35 = $84
F (60, 40) = 0.75*60 + 1.20*40 = $93
F (50, 50) = 0.75*50 + 1.20*50 = $97.50
F (40, 50) = 0.75*40 + 1.20*50 = $90
Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
