The data below shows the temperature of the water in a swimming pool over a two week period.

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

5 0

Answer:

18 °F

Step-by-step explanation:

The means are calculated in the usual way: add up the numbers and divide by the number of them. When there are a bunch of numbers, it is convenient to let a calculator or spreadsheet compute the mean for you.

In the attached, we see the mean for week 1 is 52°, and in week 2, it is 70°. The mean is 70° -52° = 18° greater in week 2.

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Someone can help??

oee [108]

Answer:

Step-by-step explanation:

let cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

$\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}} \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}$