The answer is c to the question
In the above problem, you want to find the number of multiples of 7 between 30 and 300.
This is an Arithmetic progression where you have n number of terms between 30 and 300 that are multiples of 7. So it is evident that the common difference here is 7.
Arithmetic progression is a sequence of numbers where each new number in the sequence is generated by adding a constant value (in the above case, it is 7) to the preceding number, called the common difference (d)
In the above case, the first number after 30 that is a multiple of 7 is 35
So first number (a) = 35
The last number in the sequence less than 300 that is a multiple of 7 is 294
So, last number (l) = 294
Common difference (d) = 7
The formula to find the number of terms in the sequence (n) is,
n = ((l - a) ÷ d) + 1 = ((294 - 35) ÷ 7) + 1 = (259 ÷ 7) + 1 = 37 + 1 = 38
I'm most likely wrong because I haven't learned this yet but I'm guessing .25 or 1/4
Step-by-step explanation:
Properties of the number 6425
Factorization5 * 5 * 257Square root80.156097709407Natural logarithm8.7679519097634Decimal logarithm3.8078731320033Sine-0.42867294834975
Answer:
8ax + (4a²- 6a)
Step-by-step explanation:
g(x)=4x²−6x
g(x+a)
= 4(x+a)² - 6(x+a)
= 4( x² + 2ax + a²) - 6x - 6a
= 4x² + (4)2ax + (4)a² - 6x - 6a
= 4x² + 8ax + 4a² - 6x - 6a
= 4x² + 8ax - 6x + 4a²- 6a
= 4x² + (8a - 6)x + (4a²- 6a)
g(x+a) - g(x)
= [4x² + (8a - 6)x + (4a²- 6a)] - (4x²−6x)
= 4x² + (8a - 6)x + (4a²- 6a) - 4x² + 6x
= (8a - 6)x + (4a²- 6a) + 6x
= (8a - 6 + 6)x + (4a²- 6a)
= 8ax + (4a²- 6a)
