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3 years ago

Find the sum of -44, -10, and 49

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

4 0

Answer:

-5

Step-by-step explanation:

(-44) + (-10) + 49

=> 49 - 44 - 10

=> 49 - 54

=> -5

Debora [2.8K]3 years ago

3 0

Answer:

-5

Step-by-step explanation:

We can write:

-44+(-10)+49

The negative sign flips the positive sign, so:

-44-10+49

We can solve:

-54+49

-5

Hope this helps!

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3 years ago

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denis-greek [22]

Answer:

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Step-by-step explanation:

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3 years ago

The dress store is having a sale where all the merchandise is 1/4 a women buys 24$ of merchandise at the sale price. what would

jarptica [38.1K]

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4 years ago

Read 2 more answers

How do I find the angle measurement of a rhombus

timofeeve [1]

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4 years ago

A sample of eight workers in a clothing manufacturing company gave the following figures for the amount of time(in minutes) need

lilavasa [31]

Answer:

$10.108 < \mu < 13.892$

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

We have the following distribution for the random variable:

$X \sim N(\mu , \sigma=0.45)$

And by the central theorem we know that the distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12$

The sample deviation calculated $s=2.268$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=8-1=7$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that $t_{\alpha/2}=2.36$

Now we have everything in order to replace into formula (1):

$12-2.36\frac{2.268}{\sqrt{8}}=10.108$

$12+2.36\frac{2.268}{\sqrt{8}}=13.892$

So on this case the 95% confidence interval would be given by (10.108;13.892)

$10.108 < \mu < 13.892$

7 0

3 years ago

Find the sum of -44, -10, and 49​

Find the sum of -44, -10, and 49