All categories

3 years ago

3 friendship 56 cards equally how many cards does each girl get how many cards are left over.

Mathematics

2 answers:

True [87]3 years ago

6 0

Answer:

Step-by-step explanation:

Gnoma [55]3 years ago

5 0

Answer:

The answer is 18 none left over cos friends for life.

Step-by-step explanation:

I assure you Im not using calculator :D please give me brainliest

As I need to learn my 18x table

60/3 =20

20-2=18

=18 cards each

You might be interested in

Giving brainless to anyone you can answer the question CORRECT. I’ll also give more points on a next question if you answer it r

navik [9.2K]

Answer:

1. 104

2. 52

3. 52

Step-by-step explanation:

I think this is right I maybe be wrong buthere is nottees I toooks in 6th

7 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

Domino's charges $10.99 for a large pizza.Nia just realized that she has three coupons for large cheese pizzas.each coupon is fo

strojnjashka [21]

Since she has $6 off for all the pizzas, she can get 10 pizzas with a $6 discount.
She would save $6 since, she has the discount and she would still have something left so she could buy something more if she wished to.

6 0

3 years ago

A concrete stepping stone neasures 20 square inches. what is the area of 30 such stones?

sattari [20]

If the area of one is 20, that the area of 30 is 20*30=600 square inches.

3 0

3 years ago

Simplify.... Please, I really need help.

Brilliant_brown [7]

Answer:

Step-by-step explanation:

Note that 128 = 64*2. The square root of 128 is thus 8sqrt(2). Answer B is the only one that could be correct.

7 0

3 years ago