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3 years ago

Answer for brainliest

Mathematics

2 answers:

Misha Larkins [42]3 years ago

6 0

Answer:

Step-by-step explanation:

you just add all the number together

Alja [10]3 years ago

4 0

Answer:

21 is the answer

Step-by-step explanation:

4+4+2+2+2+2+5=21

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65 POINTS PLEASE HELP

miskamm [114]

Answer:

= -----------

6(x + 7)

Step-by-step explanation:

3x - 21 x^2 - 49

----------- ÷ -------------

18x - 18 x - 1

3x - 21 x - 1

----------- × -------------

18x - 18 x^2 - 49

Factor the top left:

3x - 21 = 3(x - 7)

Factor the bottom left:

18x - 18 = 18(x - 1)

Factor the new bottom right:

x^2 - 49 = (x + 7)(x - 7)

Multiply and simplify the faction:

3(x - 7) x - 1

----------- × -----------------

18(x - 1) (x + 7)(x - 7)

= -------------

6(x + 7)

6 0

3 years ago

Read 2 more answers

4^x-4^x-1=24,then find (2x)^x

DENIUS [597]

Answer: 5²⁻⁵

<u>Step-by-step explanation:</u>

$4^x-4^{x-1}=24\\\\\\3(4^{x-1})=24\\\\\\4^{x-1}=8\\\\\\2^{2(x-1)}=2^3\\\\\\2(x-1)=3\\\\\\x-1=\dfrac{3}{2}\\\\\\x=\dfrac{5}{2}\quad \rightarrow x=2.5$

$(2x)^x\quad =(2\cdot 2.5)^{2.5}\quad =\large\boxed{5^{2.5}}$

7 0

3 years ago

The cube root of a number is 2. Write an equation, using x, that represents this situation.

Kay [80]

Answer:

x - 8 = 0

Step-by-step explanation:

Since, the cube root of a number is 2.

Let the number be x.

Therefore,

$\sqrt[3]{x} = 2 \\ cubing \: both \: sides \\ {( \sqrt[3]{x})}^{3} = {(2)}^{3} \\ x = 8 \\ x - 8 = 0$

5 0

3 years ago

Please help me out with this!

jeka94

X = 7/5 is the answer to your question

8 0

4 years ago

Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo

Anna11 [10]

I'll assume you're supposed to compute the line integral of $\nabla f$ over the given path $C$ . By the fundamental theorem of calculus,

$\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)$

so evaluating the integral is as simple as evaluting $f$ at the endpoints of $C$ . But first we need to determine $f$ given its gradient.

We have

$\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)$

Differentiating with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

and we end up with

$f(x,y)=-3\cos(xy)+C$

for some constant $C$ . Then the value of the line integral is $-3\cos192+3\cos3$ .

8 0

4 years ago